F(x)=3x^2-36

Solution for F(x)=3x^2-36 equation:

(F)=3F^2-36

We move all terms to the left:

(F)-(3F^2-36)=0

We get rid of parentheses

-3F^2+F+36=0

a = -3; b = 1; c = +36;
Δ = b2-4ac
Δ = 12-4·(-3)·36
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{433}}{2*-3}=\frac{-1-\sqrt{433}}{-6}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{433}}{2*-3}=\frac{-1+\sqrt{433}}{-6}
$